-[4z-(12z+3)]=3+(7z+0)

Solution for -[4z-(12z+3)]=3+(7z+0) equation:

Simplifying
-1[4z + -1(12z + 3)] = 3 + (7z + 0)

Reorder the terms:
-1[4z + -1(3 + 12z)] = 3 + (7z + 0)
-1[4z + (3 * -1 + 12z * -1)] = 3 + (7z + 0)
-1[4z + (-3 + -12z)] = 3 + (7z + 0)

Reorder the terms:
-1[-3 + 4z + -12z] = 3 + (7z + 0)

Combine like terms: 4z + -12z = -8z
-1[-3 + -8z] = 3 + (7z + 0)
[-3 * -1 + -8z * -1] = 3 + (7z + 0)
[3 + 8z] = 3 + (7z + 0)

Reorder the terms:
3 + 8z = 3 + (0 + 7z)
Remove the zero:
3 + 8z = 3 + (7z)
3 + 8z = 3 + (7z)

Add '-3' to each side of the equation.
3 + -3 + 8z = 3 + -3 + (7z)

Combine like terms: 3 + -3 = 0
0 + 8z = 3 + -3 + (7z)
8z = 3 + -3 + (7z)

Combine like terms: 3 + -3 = 0
8z = 0 + (7z)
8z = (7z)

Solving
8z = (7z)

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '(-7z)' to each side of the equation.
8z + (-7z) = (7z) + (-7z)

Combine like terms: 8z + (-7z) = 1z
1z = (7z) + (-7z)

Combine like terms: (7z) + (-7z) = 0
1z = 0

Divide each side by '1'.
z = 0

Simplifying
z = 0